Please provide detailed explanation/math for -qhot=qcold portion of problem. How is TF=326 k calculayed?

= 1. If 0.45 moles of liquid water at 90C are poured into a container filled with 1.3 mole of liquid water at 40C, what is the final temperature and state of your system? C (H.0(0) 75 J/(mol K) (a) 1.75 moles of water in liquid state at 440 K (b) 1.75 moles of water in liquid state at 348 K (c) 1.75 moles of water in liquid state at 326 K (d) None of the above 1 / 4 100% + 0 . 'hot - 520 14B Exam , key] 9 (0.45 mol(75 J/mol K) (TF - 363K) 33.75 T6 - 12251.25 Yold = (1.3 mol) (75 J/molk) (T4 - 313%) 97.5 T4 - 30512.5 9 acold = -33.75 TF +12251.25 = 97.577 - 305175 1.3 + 0.45 = (1.75 mol HO(1) 9 hot To total = 326 K f