Answered step by step
Verified Expert Solution
Question
1 Approved Answer
the voltage across the capacitor also changes with time as shown in Equation (3) V(t) = V + (Vsource - Vo)(1-e-t/charging), (3) where Vo
the voltage across the capacitor also changes with time as shown in Equation (3) V(t) = V + (Vsource - Vo)(1-e-t/charging), (3) where Vo = V (t) = Voe-t/discharging Qo/C is the initial voltage across the capacitor. (5) Capacitor Voltage (V) 4.0- 5 2.0- 1.5 Vow 0 5 10 charging discharging 15 Im 20 one cycle 25 Time (s) Figure 2: Voltage vs time for charging and discharging capacitor. The curve clearly shows the periodic charging (LED on) and discharging (LED off) process of a capacitor in an LED box; in addition, the filiping voltages high and Vow are also shown. Please note that in each LED on-off cycle, the on time ton is always greater than the off time toff. As evident in the figure, Vlow is the initial voltage for the charging process, while it is the initial voltage for the discharging process.
Step by Step Solution
★★★★★
3.43 Rating (153 Votes )
There are 3 Steps involved in it
Step: 1
The images provided describe the behavior of a capacitors voltage over time during charging and discharging cycles in an LED box Based on the context ...Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started