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please show all work to help me better understand. Let f(x) = 12 - x2 The slope of the tangent line to the graph of

please show all work to help me better understand.

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Let f(x) = 12 - x2 The slope of the tangent line to the graph of f(:) at the point ( - 2, 8) is The equation of the tangent line to the graph of f(x) at ( - 2, 8) is y = ma + b for m= and b = Hint: the slope is given by the derivative at c = - 2, ie. f( - 2 + h) - f( -2) lim h-+0 h

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