please show me the right way to figure out these thank you

The unit of impedance Z is Ohms. Selected Answer: @ True Answers: True False Question 10 Given the complex numbers in polar form, calculate: z1(z2 - z1)* 21 = 10 260' 27 - 4 245 Selected Answer: 117.89 _143.43: Answers: 117.89 2143.43 11.789 283.43: 4.76 477.105 47.66 4177.105 Monday, December 7, 2020 4:11:21 PM ESTor of 0.04mF An inductor of 0.25mH A capacitor of 0.25mF An inductor of 0.04mH Question 5 Calculate the equivalent impedance of the circuit below given that w = 2k rad/s, R = 40 0, L = 4mH, and C = 25UF. m Z1 Answers: 9-17 -117.25 0 -6.71 - 15.30 0 6.71 - j15.30 0 9-17 - j17.25 0 Question 6 0 out of When the imaginary part of an impedance is positive, we call that an inductive impedance. X Answers: @ True FalseHelp Center ? -6.71 - j15.30 0 6.71 - 15.30 0 9.17 + j17.25 0 Question 6 When the imaginary part of an impedance is positive, we call that an inductive impedance. X Answers: @ True False Question 7 2 0 From the series RLC circuit below, calculate the parallel circuit equivalent. C= SUF, L=0.1mH , R=60 [Recall that Yeq-1/Zeq and Reg - 1/Re(Yeq) and Xeg-1 /imaj(Yeq) ] -oa - 20k rad/s Leq Xeq Reg Zeq b R Answers: Reg - 0.1667 0. Xeg - -0.125 0 Reg - 0.06 0. Xeg - -0.08 0 Reg - 6 0. Xeg - -8 0Answers: 9.95 4 39.3 mA 9.95 4 -129.3 mA 9.95 4-39.3' mA 100.5 2 39.3 mA Question 10 Calculate the Thevenin voltage and impedance. Z1 - 5 +j2 0. Z2 - 6j 0. and Vs = 12V. Z1 oa + Z2 VTh ZTh Answers: VTh = 6.47+j4.04 V. ZTh - 2.02-j2.76 0 VTh - 6.47+j4.04 V. ZTh - 2.02-j2.76 0 VTh - 6.47-j4.04 V. ZTh - 2.02+12.76 0 WTh - 6.47-j4.04 V. ZTh - 2.02-12.76 0