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please show the detail steps for a) b) c) d) , thanks ! Assume log returns are normally and independently distributed with mean 0 and
please show the detail steps for a) b) c) d) , thanks !
Assume log returns are normally and independently distributed with mean 0 and variance 2. Then an equally weighted estimate of the variance of the log return at time t, based on the T most recent log returns, is t22=T1k=1Trtk2 Note that the usual degrees-of-freedom correction does not apply since we have assumed throughout that returns have zero mean. If the mean return is not assumed to be zero then we will replace T by T1. a. An equally weighted volatility estimate based on a sample of 30 observations is 20%. Find a two-sided 95% confidence interval for this estimate. b. Show that the standard error of variance estimator is 2/T/2 in this case. c. Show that the standard error of volatility estimator is approximately /2T in this case. d. An equally weighted volatility estimate based on a sample of 100 observations is 20%. Estimate the standard error of the estimator and find an interval for the estimate based on one-standard-error bounds. Assume log returns are normally and independently distributed with mean 0 and variance 2. Then an equally weighted estimate of the variance of the log return at time t, based on the T most recent log returns, is t22=T1k=1Trtk2 Note that the usual degrees-of-freedom correction does not apply since we have assumed throughout that returns have zero mean. If the mean return is not assumed to be zero then we will replace T by T1. a. An equally weighted volatility estimate based on a sample of 30 observations is 20%. Find a two-sided 95% confidence interval for this estimate. b. Show that the standard error of variance estimator is 2/T/2 in this case. c. Show that the standard error of volatility estimator is approximately /2T in this case. d. An equally weighted volatility estimate based on a sample of 100 observations is 20%. Estimate the standard error of the estimator and find an interval for the estimate based on one-standard-error boundsStep by Step Solution
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