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Please show your work. Thank you so much. Appreciate you! 10. An electron (e ) in a vacuum tube is slowed (i.e., decelerated) at a

Please show your work. Thank you so much. Appreciate you!

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10. An electron (e ) in a vacuum tube is slowed (i.e., decelerated) at a rate of 7.00 x 106m/$2 over a time of 6.00 ms to a final speed of 2.00 x 104 m/ s. Calculate the speed of the electron before the deceleration. (Assume the original direction of motion is positive therefore the acceleration will be negative.) [6.20 x 104 m/s] electron Vi = ? Vy = 2.00 x 104 m/s 11. A proton (p) is moving to the west when it accelerates at 2.00 x 10 m/s to the east. Since the acceleration direction is opposite the direction of motion, the proton slows down. After 9.00 ms it is travelling to the west at 5.50 x 10' m/s. Calculate the proton's initial velocity. [7.30 x 10' m/s, west] W - + E proton Vy = -5.50 x 105 m/s Vi = ? 12. A truck starts from rest (v; = 0) at a traffic light and accelerates at a rate of 4.1 m/ $2 when the light turns green. After 5.2 s the truck is at the posted speed limit and continues at a constant speed. Calculate the distance the truck accelerated. [55 m] 13. A sprinter starts from rest and accelerates 10.0 m in a time of 2.01 s. Determine the magnitude of her acceleration. [4.95 m/s ]

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