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Please solve it now ut=uxx+sin(x)BC:{u(0,t)=0u(1,t)=0Ic:u(x,0)=lnx (1) {tB.c ut=uxx+sin(x)BC:{u(0,t)=0u(1,t)=0Ic:u(x,0)=lnx (1) {tB.c

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Please solve it now

ut=uxx+sin(x)BC:{u(0,t)=0u(1,t)=0Ic:u(x,0)=lnx (1) {tB.c ut=uxx+sin(x)BC:{u(0,t)=0u(1,t)=0Ic:u(x,0)=lnx (1) {tB.c

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