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PLEASE USE MATHLAB .m 8. Pascal's triangle is an arrangement of numbers such that each row is equivalent to the coefficients of the binomial expansion

PLEASE USE MATHLAB

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.m 8. Pascal's triangle is an arrangement of numbers such that each row is equivalent to the coefficients of the binomial expansion of (x + y)(p-1), where p is some positive integer more than or equal to 1. For example, (x + y)2 = 1x2 + 2xy + 1y2 so the third row of Pascal's triangle is 1 2 1. Let Rm represent the m-th row of Pascal's triangle, and Rm(n) be the n-th element of the row. By definition, Rm has m elements, and Rm (1) = Rm (n) = 1. The remaining elements are computed by the following recursive relationship: Rm (i) = Rm-1(i 1)+Rm-1(i) for i = 2, ..., m - 1. The first few rows of Pascal's triangle are depicted in the following figure. You may assume that m is a strictly positive integer. The output variable, row, must be a row vector. 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1 1 5 10 10 5 1 Write a function with header [row] = myPascalRow (m) where row is the m-th row of the Pascal triangle. You may assume that m is a strictly positive integer. Test Cases: >> R = myPascal Row (1) R = 1 >> R = myPascalRow (2) R = 1 1 >> R = myPascal Row (3) R = 1 2 1 N

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