please write python code for this this given math question solution MEN(h)+ Kh+kah'tkght.. Substituhing "h/3" for h gives Ma Nch/3)+k, 5/3 + Kg.h? A+ kg. 63/20+... Multiply the second ege want to elemimate the term) to get equation by 3 (we 3M = 300(113)+k4h+kgh%3+kgh/a+ Substraching the top equation from this we eliminate the a term, and get i 2M= 3NCh13) -N(N) - (262/32-(843/9)ht... Evaluating this expression at h/3 gives 2M = 3N(n/a) - N(W3)-(19) (24213)12 (1/27)(8kz/)h'tan Multiply this equation by a (we want to eliminate the h2 term I to get 18M: 2711(119).an1113)-(242/3)*3(1/3)(82319843+, . substracting the equation & obave this from this one, we get 16M = 271(h/9)-12 N(8/3)+N(W) + (213) (843/9)2+.. Solving for M and and, me arranging Terms and collapsing the higher order Terms, we get +(M+=+++ [n(k) + - + 12 N(413)+++27N (141]+++ ch3) +