pls slve all thanks

3. Concerning the step potential barrier problem shown here: a. If A2B2 is reflection, then transmission is: 1A2B2=1(k1+k2k1k2)2=(k2+k1)24k1k2 Given that the C wave is the transmitted wave, should the transmission be equal to A2C2 ? For this problem calculate AC, and then A2C2, using any of the tools available to you. (5 pts) b. In pt. a you found that transmission, 1A2B2, is in fact not equal to A2C2. The reason is that the C wave moves slower than either the A or B waves because the particle has less kinetic energy in region II. The proper way to do this calculation is to take the flux of the C wave and divide it by the flux of the A wave. Please calculate the flux of the A and C waves using the flux operator: 2mi{xx} and then divide the flux of the C over A. (5 pts) C. The expression from pt. b is A2k1C2k2, so insert: AC=k2+k12k1 into A2k1C2k2 and compare the results to the known expression for transmission: 1A2B2=(k2+k1)24k1k2. (3 pts)