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pls solve it Which one of the following is closest to the area of the part of paraboloid z = 10 - x2 - y
pls solve it
Which one of the following is closest to the area of the part of paraboloid z = 10 - x2 - y above the plane z = 1 in the first octant? Note that the area of the surface z = f (x, y), (x, y) ID isA = JJ \\fx +f2 + 1dA. a) 36.18 O b) 29.33 O c) 40.71 O d) 68.47 O e) 47.18 Of) 51.27Step by Step Solution
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