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posting this question 4th time... but every time expert try to cheat and give me irrelevant and wrong Solution. kindly answer only if you have
posting this question 4th time... but every time expert try to cheat and give me irrelevant and wrong Solution. kindly answer only if you have right solution. Thanks
Question 7: Let n > 2 be an integer, and let A[1...n] be an array storing n pairwise distinct numbers. It is easy to compute the two smallest numbers in the array A: Using n - 1 comparisons, we find the smallest number in A. Then, using n - 2 comparisons, we find the smallest number among the remaining n - 1 numbers. The total number of comparisons made is 2n 3. By a similar argument, we can find the smallest and largest numbers in A using 2n - 3 comparisons. In this question, you will show that the number of comparisons can be improved. (7.1) Consider the following algorithm TwoSMALLEST(A, n), which computes the two smallest numbers in the array A: Algorithm TWOSMALLEST(A, n): if A[1]Step by Step Solution
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