power plant question, please solve it in detail correctly, thank you.

The feed solution with 1% salt is introduced at 50C under 1 bar into an evaporator. The brine leaves the evaporator concentrated at 1 bar and at its boiling point. The evaporated water is discharged as saturated steam at 1 bar. The heat required for evaporation is provided by saturated steam at 2 bar condensing inside a coil. Assuming that the two salt solutions have the same thermal properties as pure water. It will also be assumed that the heat capacity of water is constant between 50 and 99.6C, and equal to 4.18kJ.kg1.C1. We will use the steam tables or the formulas Pvap =(eb/100)4 and Lv()=25352.9kJ.kg1. Calculate the amount of steam at 2 bar that must be condensed to evaporate 1kg of water. Rponse: A=2kg,B=1kg,V=1kg,G=1.22kg