Pre Calc Quiz Review

If a parabola's focus is at (3, 8) and directrix is at y = 2, what is the vertex form of the equation representing this parabola? Oy= (2-3)2+5 Oy= (x -3)2+3 oy=!(x+3)2 +8 Oy= -17(2+3)2 -5y =2 - -1 -0 N --1 P (x, y ) -2 -3 --4 F ( 3, -4) --5 What is the equation of the parbola shown below, given the focus at F(3, -4) and the directrix y = 2? Identify the vertex and the equation of the axis of symmetry of the parabola.O y= 1 (x+ 3)2 - 1; vertex (3, -1); axis of symmetry is = = 3 = - 12(2 - 3)2 - 1; vertex (3, -1); axis of symmetry is z = Oy= -+(x - 3)2 + 1; vertex (-3, 4); axis of symmetry is = = -3 O y= (x + 4)2 + 3; vertex (-3, 4); axis of symmetry is = = 2The equation of a quadratic relation is y = = (@ - 3) + 3. Every point on this conic is equidistant from the focal point (a, b) and the line defined by y = c. Determine the value of a + b + c. 0 9 O 10 0 7 O 8Find the centre and radius of the circle a' + y' + 6x - 4y -23 = 0. O centre (3, 2), radius 6 O centre (-3, -2), radius 6 O centre (-3, 2), radius V6 O centre (-3, 2), radius 6What is the equation of the circle with centre (?, 0 ) and radius 4? O (2x - 1)2 2 + yz = 16 O (2x - 1)2 4 - yz = 16 O (2x - 1)2 4 + y' =4 O (2x - 1)2 + yz = 16 4Write the equation of a circle with centre (-8, -3 ) which is tangent to the r-axis. O (x + 8)2 + (y + 3)2= 3 O (x - 8)2 + (y - 3)2 = 3 O (x - 8)2 + (y -3)2 =9 O (x + 8)2 + (y + 3)2= 9The point (k, 3) lies on the ellipse y 32 + 18 = 1. Which of the following could be a value for k? O 8V/2 0 4 0 6 O 3V/2