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Princeton MCAT Content Review Maths and Physics 1) V=EMF+IR used when batteries are charging why wouldnt it simply be EMF=V IR is usually lost by

Princeton MCAT Content Review Maths and Physics

1) V=EMF+IR used when batteries are charging why wouldnt it simply be EMF=V IR is usually lost by the resistor but why do we add it in the formula. Please explain, and an image would really help.

2) Electrical potential is the work done to a charge to move it to a specific position which then becomes potential energy. The voltage is the difference in the potential which is what is confusing me. ie: positive terminal has high potential more work is needed per coloumbs to place it in the position. While negative terminal is less work needed per couloumbs. But the potential difference is not the difference between the potential of the positive terminal and the negative terminal, it is the work needed to push a charge from the positive terminal to the negative terminal? This is confusing me.

Why is the potential higher near the source charge. Is it because we consider the charge that is moved to be positive so more work is needed tk push a positive charge next to a positive source charge? (Why is the potential higher near the source charge?)

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