Probability Distribution

Last year, the numbers of skateboards produced per day at a certain factory were normally distributed with a mean of 20,500 skateboards and a standard deviation of 55 skateboards.

On what percent of the days last year did the factory produce 20,555 skateboards or fewer?

On what percent of the days last year did the factory produce 20,610 skateboards or more?

On what percent of the days last year did the factory produce 20,445 skateboards or fewer?

P ( x5 205 55) = P (2= 20565 - 20500 ) = p ( $5 ) = 1=, 8413 = 84.13% P ( X 2 20610 ) = P (2= 20610 - 20800 55 = p ( 1 10 ) = 2 =. 97 72 = 97. 72% P ( x 2 20610 ) = P ( 2= 20445- 20500 55 ) = P(- 35 ) = -1=1-1587 =, 8413 84. 13% EXPO