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Corn: In a random sample of 88 ears of corn, farmer Carl nds that 9 of them have worms. He wants to find the 90% confidence interval for the proportion of all his corn that has worms. (a) What is the point estimate for the proportion of all of Carl's corn that has worms? Round your answer to 3 decimal places. :I (b) What is the critical value ofz (denoted 2,42) for a 90% condence interval? Use the value from the table orr if using software, round to 2 decimal places. 2m = |:| (c) What is the margin of error (E) for a 90% confidence interval? Round your answer to 3 decimal places. (d) Construct the 90% confidence interval for the proportion of all of Carl's corn that has worms. Round your answers to 3 decimal places. (e) Based on your answer to part (d), are you 90% condent that less than 19% of Carl's corn has worms? 0 Yes, because 0.19 is above the upper limit of the condence interval. 0 No, because 0.19 is below the upper limit of the confidence interval. 0 No, because 0.19 is above the upper limit of the confidence interval. 0 Yes, because 0.19 is below the upper limit of the confidence interval