probability of approximately $0\mathrm{.}01.$

$z=\frac{(\stackrel{}{x})-}{\sqrt[\phantom{2}]{n}}2\mathrm{.}33$

$\frac{(\stackrel{}{x})-1,400}{20\mathrm{.}207}2\mathrm{.}33$

$\stackrel{}{x}$

$k$