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Problem 1. (1 point) It is easy to check that tor any value etc. the tunction -2 c yx+;2 is solution of equation x}?! +

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Problem 1. (1 point) It is easy to check that tor any value etc. the tunction -2 c yx+;2 is solution of equation x}?! + 23; = 4x2, ()4: b 0). Find the value of c for which the solution satisfies the initial condition y(4) = 2. c

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