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Problem 1 Consider the following assembly code . LCO .string ans %d main: LFB0: pushq %rbp movq %rsp, %rbp subq $16, %rsp movl $0,
Problem 1 Consider the following assembly code . LCO .string "ans %d " main: LFB0: pushq %rbp movq %rsp, %rbp subq $16, %rsp movl $0, 4%rbp) movabsq movq %rax, -16(%rbp) $58217882423726, %rax .L2: movq -16(%rbp), %rax andl $1, Xeax movi %eax, %eax movi -4(Arbp), %eax xor1 %eax, %eax movl %eax, -4(Xrbp) shrq16(%rbp) cmpq $e 16(rbp) jne L2 movl -4(Xrbp), %eax movl %eax, %esi movl $0, eax call printf mov1 $e, %eax leave ret This code came from skeleton C file below after optimizing with O0. This means gcc -00 -S command was used to convert C File into assembly file Complete the C code given below using the provided assembly code Step 1 might be to ignore the skeleton file and create a equivalent C code from the assembly code, and then rewrite the code to fit the skeleton file 60 points (10 points per blank) int main() int output unsigned long value do output while (value 0x printf("ans %d ", return 0; output)
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