A 70.0 kg grindstone is a solid disk 0.540 m in diameter. You press an ax down on the rim with a normal force of F = 170 N (Figure 1). The coefficient of kinetic friction between the blade and the stone is 0.60, and there is a constant friction torque of 6.50 N - m between the axle of the stone and its bearings. Figure < 1 of 1 m = 50.0 kg Part A How mach torce must be applied tangestaly at the end of a crarik handle 0.500 w kng ko bing the aona from rar so 120 rer/ min in & 00 x? Expross your answer with the appropriate units. Value Units Part B After the grindstone attains an angular speed of 120 rev/min, what tangential force at the end of the handle is needed to maintain a constant angular speed of 120 rev/min? Express your answer with the appropriate units. H ? F2 = Value Units Part C How much time does it take the grindstone to come from 120 rev/min to rest if it is acted on by the axle friction alone? Express your answer with the appropriate units. t = Value Units