Problem 11 YA If we place an electric dipole in a homogeneous 300N/C E = 300N/C electric field as shown in the picture, what are magnitude 21 =-1.5uC and direction of the torque on the electric dipole? Clearly draw the torque's vector in the picture on the side. 60 0.5m *, 30 300,* 02 = +1.5uC Under the effect of the electric force on Q1 directed X * 30 120 p upward to the right, and the electric force on Q2 30 directed to the downward to the left, the electric dipole will rotate clockwise in the plane of the page; therefore, the torque associated with the rotation will be directed perpendicular into the page: 8 7 Ipl = |ql| = 1.5 x 10-6C x 0.5m = 7.5 x 10-7Cm 17| = [p x E| =\\pllE | sin (@) |7| = 7.5 x 10-7Cm x 300- x sin (120) |7| = 1.9486 x 10-4Nm