Problem 2 A 10 g bullet with speed Vbulleto is fired into a 1.000 kg wood block (vblocko = 0), where it lodges. Subsequently, the block slides 4.0 m across a wood floor (Mk = 0.20 for wood on wood). What was the bullet's speed Vbulleto? The block slides 4.0m before stop. so the velocity just after collision of can be calculated as: v4 - 0 = 2as = Vb = 4m/s Where a = /kg From the conservation of momentum: mbullet Vbulleto = (mbullet + Mblock) Uf Plug in number and get Vbulleto Answer: 400m/s