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Problem # 2 : Polyalphabetic substitution Using polyalphabetic substitution, with alphabet a z ( no caps ) , spaces translated to an underscore character (
Problem #: Polyalphabetic substitution
Using polyalphabetic substitution, with alphabet az no caps
spaces translated to an underscore character and a period as
the last character of the alphabet use the private key security to
encrypt and then decrypt the plaintext message: sendmoney
To help you, use the following formula:
Encryption: ciphertext plaintext key mod
Decryption: plaintext ciphertext key mod
Number your alphabet so that it starts with zero, eg A Z
This means that your alphabet will
be abcdefghijklmnopqrstuvwxyz
Be sure to show all work. No credit will be given without showing each
step in the process.
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