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Problem # 2 : Polyalphabetic substitution Using polyalphabetic substitution, with alphabet a z ( no caps ) , spaces translated to an underscore character (

Problem #2: Polyalphabetic substitution
Using polyalphabetic substitution, with alphabet az (no caps),
spaces translated to an underscore character (_), and a period (., as
the last character of the alphabet), use the private key security to
encrypt and then decrypt the plaintext message: send_money
To help you, use the following formula:
Encryption: ciphertext =(plaintext + key) mod 28
Decryption: plaintext =(ciphertext - key) mod 28
Number your alphabet so that it starts with zero, e.g., A =0, Z=25,_=
26,.=27. This means that your alphabet will
be abcdefghijklmnopqrstuvwxyz_.
Be sure to show all work. No credit will be given without showing each
step in the process.

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