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Problem # 3 (Process calculation for fluid as ideal gas under different paths) The state of an ideal gas with CP=(5/2)R is changed from P1=1

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Problem \# 3 (Process calculation for fluid as ideal gas under different paths) The state of an ideal gas with CP=(5/2)R is changed from P1=1 bar and V1=12m3 to P2=12 bar and V2=1m3 by the following mechanically reversible processes: (a) Isothermal compression. (b) Heating at constant volume followed by cooling at constant pressure. Calculate Q,W,U, and H for each of these processes, and sketch the paths of all processes on a single PV diagram

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