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Problem 4: A closed hollow cylinder (i.e., with capped ends) is situated in an electric field given by E(u) = Eo(u i + 7j +

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Problem 4: A closed hollow cylinder (i.e., with capped ends) is situated in an electric field given by E(u) = Eo(u i + 7j + 22k). The cylinder's axis is on the x-axis with its L center at the origin. The cylinder's height is L and its radius is R. Here u = x/x0 is a dimensionless variable, where xo sets the scale of the field. Refer to the figure. Acharya, X R Otheexpertta.com Part (a) Integrate to find an expression for the total electric flux through the cylinder in terms of defined quantities and enter the expression. Expression _ Q = Select from the variables below to write your expression. Note that all variables may not be required. a, B, n, 0, d, Eo, g, h, j, L, m, P, R, t, x0 Part (b) For L = 5.6 m, R = 0.11 m, Eo = 6.5 V/m, and x0 = 1 m, find the value of the electric flux, in units of voltmeter, through the cylinder. Numeric _: A numeric value is expected and not an expression. Part (c) If the electric field is E(u) = Eo(323uzi + 42j + 415k), enter an expression for the total flux in terms of defined quantities. Expression _ P'= Select from the variables below to write your expression. Note that all variables may not be required. a, B, n, 0, d, Eo, g, h, j, k, L, m, P, R, t

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