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Problem 4 (Braess Paradox): Consider a simple network with one OD connected by two routes and four links. The total demand is 6 units. The
Problem 4 (Braess Paradox): Consider a simple network with one OD connected by two routes and four links. The total demand is 6 units. The link travel time functions are: t1(x) = 50 + x1; a) Solve for the UE flows on the network. Assume now that the local transportation authority decides to expand the transportation network to improve flow and reduce delay. This is to be accomplished by building a new highway connecting the two intermediate nodes as shown in the new network below. In the new network, a fifth link is added, which provides a third route for the OD. The travel time on the new link is: ts(xs) 10 +x 4 a-6 Problem 4 (Braess Paradox): Consider a simple network with one OD connected by two routes and four links. The total demand is 6 units. The link travel time functions are: t1(x) = 50 + x1; a) Solve for the UE flows on the network. Assume now that the local transportation authority decides to expand the transportation network to improve flow and reduce delay. This is to be accomplished by building a new highway connecting the two intermediate nodes as shown in the new network below. In the new network, a fifth link is added, which provides a third route for the OD. The travel time on the new link is: ts(xs) 10 +x 4 a-6
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