Problem 5 Precious metals are assets that people acquire to hedge against inflation. Here are the prices as of February 6, 2020. Precious Metal Spot Price ($/Oz) (dollars per ounce) $ Change Gold 1559.33 4.00 Silver 17.68 0.01 Platinum 967.95 (.19) Palladium 2445.30 (6.36) You'll be writing a program to help manage your funds. Some reflection before you begin programming-the problem is much simpler than it might seem. We'll give an example. Suppose you have $100. Apples cost $27 each. What's the maximal number of apples you can buy and what amount of money will be left over? Here's a minisession you should do on your own to help better understand. 1 >>> wallet = 100 2 >>> appleCost = 27 3 >>> apples = wallet/appleCost 4 >>> apples 5 3.7037037037037037 6 >>> import math 7 >>> apples = math.floor(apples) 8 >>> apples 93 10 >>> myFloor = wallet // appleCost 11 >>> myFloor 12 3 13 >>> left = wallet % appleCost 14 >>> left 15 19 16 >>> wallet - apples appleCost 17 19 18 >>> 19 + 3+27 == 100 19 True Assignment No 3 Functions and Choice Page 20 Listing 2: precmetal.py program 1 #imports 2 import math 4 ###################################### 6 # DATA 7 # 8 #All values $/ounce abbreviated $/Oz 9 Gold = 1559.10 10 Silver = 17.68 11 Platinum = 967.95 12 Palladium = 2445.30 14 Au, Ag, Pi, Pa = "AU", "Ag", "P1", "Pa" # to make use of symbols easier 16 account = 100000# $100,000 cash assets 17 Au_amt, Ag_amt, Pl_amt, Pa_amt = 0,0,0,0 18 19 ####################################### 20 #PARAMETERS NOTHING 21 #RETURN amount of money you have 22 #and amount of precious metals 23 def holdings(): print("Your current holdings") print("Account = {0:2f}".format(account)) print("Gold = ", Au_amt) print("Silver = ", Ag_amt) print("Platinum = ", Pl_amt) print("Palladium = ", Au_amt) print 33 #PARAMETERS metal and amount in ounces you want to purchase 34 #RETURN the cost of the amount of metal you're purchasing (Numerical) 35 def precious MetalToDollars (metal, amt): # TODO: Implement Function pass 40 #PARAMETERS metal and amt you want to purchase 41 #RETURN IF you have sufficient funds, purchase that amount in 42 #oz. and add to x_amt and subtract that from account 43 # and RETURN message 44 #If you don't have sufficient funds, RETURN message that you 45 #can't purchase that amount 46 def purchase(metal, amt): Assignment No 3 Functions and Choice Page 21 global account # global is not to be used without being told, # needed specifically for this problem global Au_amt global Ag_amt global Pl_amt global Pa_amt #LEAVE GLOBAL variables # TODO: Implement Function # TODO: Return String specifically # Suggestion: Use format, to do a newline in a string, use in pass 61 ######MAIN###### 62 if __name__=="_main__": holdings() print("{:0.2f)". format (precious MetalToDollars(Au, 4))) print("{:0.2f}".format(precious MetalToDollars(Ag, 100))) print("{:0.2f}".format(precious MetalToDollars(Pa, 23))) print("{:0.2f}".format(precious MetalToDollars(P1, 17))) print() print (purchase (Au, 4)) print(purchase(Ag, 100)) print (purchase(Pa, 23)) print(purchase(P1, 17)) print) holdings print (purchase(P1, 100000)) Assignment No 3 Functions and Choice Page 22 Output precmetal.py Your current holdings Account = 100000.00 Gold = 0 Silver = 0 Platinum = 0 Palladium = 0 6236.40 1768.00 56241.90 16455.15 You have purchased 4 oz. of Au for $ 6236.4 You have $ 93763.6 left in your account You have purchased 100 oz. of Ag for $ 1768.0 You have $ 91995.6 left in your account You have purchased 23 oz. of Pa for $ 56241.9 You have $ 35753.700000000004 left in your account You have purchased 17 oz. of Pl for $ 16455.15 You have $ 19298.550000000003 left in your account Your current holdings Account = 19298.55 Gold = 4 Silver = 100 Platinum = 17 Palladium = 4 You have insufficient funds for 100000 oz. of Pl Deliverables for Programming Problem 5 . Complete the program above. . Only modify functions, do not add code outside of functions The draft is metalurgency.py. . Put your code for this function in a new Python module named precmetal.py. Assignment No 3 Functions and Choice Page 23 Problem 5 Precious metals are assets that people acquire to hedge against inflation. Here are the prices as of February 6, 2020. Precious Metal Spot Price ($/Oz) (dollars per ounce) $ Change Gold 1559.33 4.00 Silver 17.68 0.01 Platinum 967.95 (.19) Palladium 2445.30 (6.36) You'll be writing a program to help manage your funds. Some reflection before you begin programming-the problem is much simpler than it might seem. We'll give an example. Suppose you have $100. Apples cost $27 each. What's the maximal number of apples you can buy and what amount of money will be left over? Here's a minisession you should do on your own to help better understand. 1 >>> wallet = 100 2 >>> appleCost = 27 3 >>> apples = wallet/appleCost 4 >>> apples 5 3.7037037037037037 6 >>> import math 7 >>> apples = math.floor(apples) 8 >>> apples 93 10 >>> myFloor = wallet // appleCost 11 >>> myFloor 12 3 13 >>> left = wallet % appleCost 14 >>> left 15 19 16 >>> wallet - apples appleCost 17 19 18 >>> 19 + 3+27 == 100 19 True Assignment No 3 Functions and Choice Page 20 Listing 2: precmetal.py program 1 #imports 2 import math 4 ###################################### 6 # DATA 7 # 8 #All values $/ounce abbreviated $/Oz 9 Gold = 1559.10 10 Silver = 17.68 11 Platinum = 967.95 12 Palladium = 2445.30 14 Au, Ag, Pi, Pa = "AU", "Ag", "P1", "Pa" # to make use of symbols easier 16 account = 100000# $100,000 cash assets 17 Au_amt, Ag_amt, Pl_amt, Pa_amt = 0,0,0,0 18 19 ####################################### 20 #PARAMETERS NOTHING 21 #RETURN amount of money you have 22 #and amount of precious metals 23 def holdings(): print("Your current holdings") print("Account = {0:2f}".format(account)) print("Gold = ", Au_amt) print("Silver = ", Ag_amt) print("Platinum = ", Pl_amt) print("Palladium = ", Au_amt) print 33 #PARAMETERS metal and amount in ounces you want to purchase 34 #RETURN the cost of the amount of metal you're purchasing (Numerical) 35 def precious MetalToDollars (metal, amt): # TODO: Implement Function pass 40 #PARAMETERS metal and amt you want to purchase 41 #RETURN IF you have sufficient funds, purchase that amount in 42 #oz. and add to x_amt and subtract that from account 43 # and RETURN message 44 #If you don't have sufficient funds, RETURN message that you 45 #can't purchase that amount 46 def purchase(metal, amt): Assignment No 3 Functions and Choice Page 21 global account # global is not to be used without being told, # needed specifically for this problem global Au_amt global Ag_amt global Pl_amt global Pa_amt #LEAVE GLOBAL variables # TODO: Implement Function # TODO: Return String specifically # Suggestion: Use format, to do a newline in a string, use in pass 61 ######MAIN###### 62 if __name__=="_main__": holdings() print("{:0.2f)". format (precious MetalToDollars(Au, 4))) print("{:0.2f}".format(precious MetalToDollars(Ag, 100))) print("{:0.2f}".format(precious MetalToDollars(Pa, 23))) print("{:0.2f}".format(precious MetalToDollars(P1, 17))) print() print (purchase (Au, 4)) print(purchase(Ag, 100)) print (purchase(Pa, 23)) print(purchase(P1, 17)) print) holdings print (purchase(P1, 100000)) Assignment No 3 Functions and Choice Page 22 Output precmetal.py Your current holdings Account = 100000.00 Gold = 0 Silver = 0 Platinum = 0 Palladium = 0 6236.40 1768.00 56241.90 16455.15 You have purchased 4 oz. of Au for $ 6236.4 You have $ 93763.6 left in your account You have purchased 100 oz. of Ag for $ 1768.0 You have $ 91995.6 left in your account You have purchased 23 oz. of Pa for $ 56241.9 You have $ 35753.700000000004 left in your account You have purchased 17 oz. of Pl for $ 16455.15 You have $ 19298.550000000003 left in your account Your current holdings Account = 19298.55 Gold = 4 Silver = 100 Platinum = 17 Palladium = 4 You have insufficient funds for 100000 oz. of Pl Deliverables for Programming Problem 5 . Complete the program above. . Only modify functions, do not add code outside of functions The draft is metalurgency.py. . Put your code for this function in a new Python module named precmetal.py. Assignment No 3 Functions and Choice Page 23