Problem 5.10 Let X be the diameter (in mm) of a seed of a certain plant. It can be shown that ln(X) is normally distributed with mean = 0.68 ln(mm) and = 0.22 ln(mm). (a) Compute P(X > 2) and P(X 1). (b) Find the 50-th percentile of X, i.e. find a value x0 such that P(X x0) = 0.5.