Question
Problem Set 5.1: One-Variable Chi-Square in SPSS (1) Criterion : Calculate a chi-square analysis in SPSS. Data :Tandy's Ice Cream shop serves chocolate, vanilla, and
Problem Set 5.1:
One-Variable Chi-Square in SPSS (1)
- Criterion: Calculate a chi-square analysis in SPSS.
- Data:Tandy's Ice Cream shop serves chocolate, vanilla, and strawberry ice creams. Tandy wants to examine planning for the future years. She knows that on average she expects to purchase 100 cases of chocolate, 75 cases of vanilla, and 25 cases of strawberry (4:3:1). This year, her sales increased and she purchased 125 cases of chocolate, 80 cases of vanilla, and 35 cases of strawberry.
- Instruction:Complete the following steps:
a.Open SPSS and create New DataSet.
b.Go to theVariable Viewtab and enter Flavor in row 1 and Frequency in the row 2. Adjust the decimal value to 0. Go toValuesin theFlavorrow and enter 1 for chocolate, 2 for vanilla, and 3 for strawberry, and clickOK.
c.Go to theData Viewtab and under theFlavorcolumn, enter 1 in row 1, 2 in row 2, and 3 in row 3. Under the frequency column, enter 125 in row 1, 80 in row 2, and 35 in row 3.
d.In the Toolbar, clickData, and then selectWeight Cases.
e.ClickWeight Cases By, clickFrequency, and then clickArrowto send it over to theFrequency Variablebox. ClickOK.
f.In the Toolbar, clickAnalyze, thenNonparametric Tests, thenLegacy Dialogs, and thenChi-Square.
g.ClickFlavorand then clickArrowto send to theTest Variable Listwindow.
h.UnderExpected Values, selectValue, and then enter the following three values in the given order: 100, 75, 25.
i.ClickOKand copy and paste the output to your Word document.
Flavor
Observed N
Expected N
Residual
Chocolate
125
120.0
5.0
Vanilla
80
90.0
-10.0
Strawberry
35
30.0
5.0
Total
240
Test Statistics
Flavor
Chi-Square
2.153a
df
2
Asymp. Sig.
.341
- 0 cells have expected frequencies less than 5.The minimun expected cell frequency is 30
Answer this:Was Tandy's distribution of proportions the same as expected?No. Tandy's expectations for chocolate and strawberry were less than the observed proportions (both +5) and Tandy's expectations for vanilla were higher than the observed proportions (-10).
this was the feedback to my answer Your SPSS looks good. To improve, reconsider how to interpret the Chi-Square results. The response as to whether or not Tandy's distribution of proportions was as expected needs to be reviewed, using the SPSS output to support the conclusions drawn.
what did I do wrong?
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