Question
problem/question: Write two functions that adds the previous two numbers to N times. The first function will return `int` while taking 3 `int` as parameters.
problem/question: Write two functions that adds the previous two numbers to N times. The first function will return `int` while taking 3 `int` as parameters. The second function will return `double` while taking 2 `double` and an `int` as parameters. Following are the signature of the functions: static int sumPrevTwo(int first, int second, int n) { // TODO: CODE GOES HERE } static double sumPrevTwo(double frist, double second, int n) { // TODO: CODE GOES HERE }
some type of example:
```java // PLEASE CALL THESE INSIDE THE MAIN AND TEST OUT THE RESULTS // NOTE: IF YOU JUST PRINT OUT THE RESULTS, YOU WILL NOT GET ANY POINTS public static void main(String[] args) { // TEST CASES System.out.println(sumPrevTwo(0, 1, 5)); // EXPECTED 5 System.out.println(sumPrevTwo(1, 2, 6)); // EXPECTED 21 System.put.println(sumPrevTwo(3.1, 3.2, 10)); // EXPECTED 281.4 }
``` Explanation for 0, 1, 5: S0 = 0, S1 = 1, S2 = 1, S3 = 2, S4 = 3, S5 = 5 Explanation for 1, 2, 6: S0 = 1, S1 = 2, S2 = 3, S3 = 5, S4 = 8, S5 = 13, S6 = 21 Explanation for 3.1, 3.2, 10: S0 = 3.1, S1 = 3.2, S2 = 6.3, S3 = 9.5, S4 = 15.8, S5 = 25.3, S6 = 41.1, S7 = 66.4, S8 = 107.5, S9 = 173.9, S10 = 281.4
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