Processor Ahas a clock rate i.e., switching frequency) of 2.5 GHz and supply voltage of 22 V. Assume that, on average, it consumes 60 W of static power and 125 W of dynamic power. Suppose the supply voltage (Vdd) of Processor A was tripled to 6.6 V, but all other quantities - capacitive load (C), switching frequency (F), and leakage current (Idd) - remain unchanged. What are the new values of A's static and dynamic power, and also its total power? (Reminder: Please DO NOT put commas within numbers. For example, write 1000, not 1,000.) Processor A's new static power = EW Processor A's new dynamic power = Processor A's new total power Click to see additional instructions Processor B has a clock rate of 6 GHz, a supply voltage of 1.5 V, a leakage current of 3 A, and it consumes 80 W of dynamic power. Suppose the clock rate (switching frequency) of Processor B was halved to 3 GHz, the supply voltage was doubled to 3 V, and the leakage current was halved to 1.5 A, but the capacitive load (C) remains unchanged. What are the new values of B's static and dynamic power, and also its total power? Processor B's new static power = Processor B's new dynamic power Processor B's new total power =