Prof. Modyn proposes a multi-step, steady-state approach to cooling low-pressure steam before it's exhausted to the ambient. The steam enters a compressor at 1.50 kg/s, 0.100 MPa, and 285 C where it is adiabatically compressed to 1.20 MPa requiring 2550 kW. The water is then feed to a well-insulated counter-current heat exchanger where it is isobarically cooled with air flowing at 1.14 kmol/s. The air enters the exchanger at 25.0 C and leaves at 185 C. Lastly, the water is fed to a well-insulated throttle valve where it is reduced back to 0.100 MPa forming a 2-phase product. Neglect changes in kinetic and potential energy. Assume air is an ideal gas with p [kJ/kmol-K] = 27.9 +4.78 x 10-3T with T in K. Calculate the heat interaction term of the air, Qair (kW). kW Calculate the exiting enthalpy of the water, he water (kJ/kg). kJ/kg Calculate the mass flow rate of liquid water recovered in the process, mliq (kg/s). kg/s