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proof it Theorem 6.10 (Orthogonality property) 0exxkLnk(x)Lmk(x)dx=n!(n+k)!nn Theorem 6.10 (Orthogonality property) dx n!

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Theorem 6.10 (Orthogonality property) 0exxkLnk(x)Lmk(x)dx=n!(n+k)!nn

Theorem 6.10 (Orthogonality property) dx n!

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