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prove by induction 1^2+2^2 + 3^2 + ... + (2n)^2 = n(2n+1)(4n+1) / 3 for the first 2n positive integers.
prove by induction
1^2+2^2 + 3^2 + ... + (2n)^2 =
n(2n+1)(4n+1) / 3
for the first 2n positive integers.
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