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prove by induction: 2. Given a function over positive integers, where F(0)=0; and F(n)=1+F(floor(n/2)). Then show that F(n)=1+floor(loga(n)). Here floor(n/2)(n-1)/2 if n is odd and
prove by induction:
2. Given a function over positive integers, where F(0)=0; and F(n)=1+F(floor(n/2)). Then show that F(n)=1+floor(loga(n)). Here floor(n/2)(n-1)/2 if n is odd and n/2 if n is even. (5 points) Step by Step Solution
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