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Prove that Decision - LWE is as hard as Search - LWE. Specifically, show a divide - and - conquer attack, where given an adversary

Prove that Decision-LWE is as hard as Search-LWE. Specifically, show a divide-and-conquer attack, where given an adversary who solves Decision-LWE, it is possible to guess the entries of s one by one. Recall that the modulus p is polynomial in the security parameter.
Hint: Consider guessing the value of the first entry of s, denoted s1 in Zq and choosing a column vector a in Z_p^m uniformly at random. Given an LWE instance (A, u), update the instance to (A, u + s1 a mod p), where A is the matrix A with column vector a added to its first column.
What is the distribution of (A, u + s1 a mod p) in case the guess for s1 is correct or incorrect?

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