Prove that the Internet checksum computation shown in the text is independent of byte order (host order or network order) except that the bytes in the final checksum should be swapped later to be in the correct order. Specifically, show that the sum of 16-bit words can be computed in either byte order. For example, if the one's complement sum (denoted by of 16-bit words is represented as follows, the following swapped sum is the same as the original sum above: Prove that the Internet checksum computation shown in the text is independent of byte order (host order or network order) except that the bytes in the final checksum should be swapped later to be in the correct order. Specifically, show that the sum of 16-bit words can be computed in either byte order. For example, if the one's complement sum (denoted by of 16-bit words is represented as follows, the following swapped sum is the same as the original sum above