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Prove whether or not S is a CFL. S={w {a,b,c}*|#a(w) = #b(w) and #b(w) #c(w)(mod3)} #b(w) #c(w)(mod3) means that #b(w) mod 3 =#c(w) mod 3
Prove whether or not S is a CFL.
S={w
{a,b,c}*|#a(w) = #b(w) and #b(w) 
#c(w)(mod3)}
#b(w) 
#c(w)(mod3) means that #b(w) mod 3 =#c(w) mod 3
If it is CFL, please draw a PDA for it.
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Secrets Of Analytical Leaders Insights From Information Insiders
Authors: Wayne Eckerson
1st Edition
1935504347, 9781935504344
