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Provide a dynamic programming solution to each problem by following the described steps. You need to complete steps ( a ) , ( c )
Provide a dynamic programming solution to each problem by following the described steps.
You need to complete steps acd and e for all problems, but it will suffice to complete steps b and f only for one of the problems:
Steps:
aIdentify the "last" decision you need to make to compute the value of the optimal solution.
For example, for rod cutting, the last decision we need to make is the length of the first cut we will make.
b Define and prove optimal substructure. This entails applying the statement "the solution to the larger problem cannot use suboptimal solutions to subproblems" to the specific problem in hand.
cDefine subproblems ie the table you are trying to compute express the value of the optimal solution for the overall problem in terms of the values of the optimal solutions to subproblems.
dFormulate a recursive solution to compute the value of the optimal solution for subproblems.
Do not forget to specify the base cases
eCharacterize the runtime of the resulting procedure assuming that you would implement your solution using a bottomup procedure.
fProvide the pseudo code of the bottomup procedure you use to compute the value of the optimal solution, as well as the procedure for reconstructing the optimal solution. As an exercise that will help connect the abstract solution here to a real computer program, you may also want to implement this procedure using a programming language of your choice and test your code. But this is up to you and you do not need to submit anything in that regard.
We are given types of coin denominations with integer values dots, Given an
integer we would like to compute the minimum number of coins to make change for ie
we would like to compute the minimum number of coins that add up to where repetitions
are allowed We know that one of the coins has value so we can always make change for
any amount of money For example, if we have coin denominations of and then the
optimal solution for is
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