public class Coin {

/** Internal representation of coin showing heads. */

public static final int HEADS = 0;

/** Internal representation of coin showing tails. */

public static final int TAILS = 1;

/** Coin's current face showing. */

private int face;

/**

* Constructs a Coin object and flips it to give it a starting value.

*/

public Coin() {

flip();

}

/**

* Flips this Coin by randomly choosing a face value.

*/

public void flip() {

face = (int) (Math.random() * 2);

}

/**

* Returns true if the current face of the Coin is heads.

* @return true if current face is heads, else false.

*/

public boolean isHeads() {

return (face == HEADS);

}

/**

* Returns the current face value of this Coin as a String.

* @return toString description

*/

public String toString() {

String faceName;

if (face == HEADS) {

faceName = "Heads";

} else {

faceName = "Tails";

}

return faceName;

}

}

There is a very simple Coin class in chapter 5 of the text. You can find it in the COMP 1510 Examples project in the chapter 5 package. Copy it to your lab 9 project.

Lets write a program called CoinRunner. CoinRunner only contains a main method.

Inside the main method, you will need to declare and instantiate a Coin.

Using a for loop, flip the coin 100 times. Determine the longest run of heads in 100 flips

of the coin:

Suppose we flip the coin 10 times: H, H, H, H, T, T, T, H, H, T. The longest run of

heads in this case is 4.

Suppose we flip the coin 5 times: H, T, H, H, T. The longest run of heads in this

case is 2.

Your program should print out the length of the longest run of heads. For example, we

flipped a coin 10 times and the output looked like this:

 Tails Tails Heads Heads Heads Heads Heads Heads Tails Heads The longest run of heads is 6