Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

public static String mystery (String s) { char []temp = new char[1]; if (s.equals()) return; if(aeiouAEIOU.indexOf(s.charAt(0)) != -1) { temp[0]=s.charAt(0); return new String(temp) + mystery(s.substring(1));

public static String mystery (String s)

{

char []temp = new char[1];

if (s.equals("")) return"";

if("aeiouAEIOU".indexOf(s.charAt(0)) != -1)

{

temp[0]=s.charAt(0);

return new String(temp) + mystery(s.substring(1));

}

else return "" + mystery(s.substring(1));

}

a) show all the call to the function and what each one returns to its predecessor?

String result = mystery ("Omar");

Call#

1. mystery("Omar") returns ____ to result

2. mystery("___") returns _____ to Call ____

3. mystery ("__") returns ____ to Call #2.

4. mystery ("__") returns ____ to Call ___

5. mystery ("") returns "" to Call#4

b) Describe what the mystery method accomplishes

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image_2

Step: 3

blur-text-image_3

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

DB2 9 For Linux UNIX And Windows Advanced Database Administration Certification Certification Study Guide

Authors: Roger E. Sanders, Dwaine R Snow

1st Edition

1583470808, 978-1583470800

More Books

Students also viewed these Databases questions

Question

What must a creditor do to become a secured party?

Answered: 1 week ago

Question

When should the last word in a title be capitalized?

Answered: 1 week ago

Question

how would you have done things differently?

Answered: 1 week ago

Question

3. What information do participants need?

Answered: 1 week ago