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Python: I'm creating a program that prints n subintervals of equal length where lenth is (b-a). I seem to be outputting a long list of
Python: I'm creating a program that prints n subintervals of equal length where lenth is (b-a). I seem to be outputting a long list of (1,1) intervals. How do I fix the code to display 8 subintervals of the interval (0, 2pi)? I approximated pi by using 22/7 in its place.
In [*]: a = 0\# defines the first element of our interval (a,b) b = 2*(22 /7) # defines the last element of our interval (a,b) n = 8 # defines the number of equidistant subintervals that divides (a,b) i a # defines the starting point necessary for the following conditional statement while iStep by Step Solution
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