python programming:

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Exercise 2.10: The semi-empirical mass formula In nuclear physics, the semi-empirical mass formula is a formula for calculating the approximate nuclear binding energy B of an atomic nucleus with atomic number Z and mass number A: B = a1 A - a2A2/3 22 (A -22) + as 41/2' where, in units of millions of electron volts, the constants are a1 = 15.8, az = 18.3, az = 0.714, 24 = 23.2, and 23 - 04 A1/3 25 = 0 if A is odd, 12.0 if A and Z are both even, -12.0if A is even and Z is odd. a) Write a program that takes as its input the values of A and Z, and prints out the binding energy for the corresponding atom. Use your program to find the binding energy of an atom with A = 58 and Z = 28. (Hint: The correct answer is around 500 MeV.) b) Modify your program to print out not the total binding energy B, but the binding energy per nucleon, which is B/A. C) Now modify your program so that it takes as input just a single value of the atomic number 2 and then goes through all values of A from A = Z to A = 32, to find the one that has the largest binding energy per nucleon. This is the most stable nucleus with the given atomic number. Have your program print out the value of A for this most stable nucleus and the value of the binding energy per nucleon. d) Modify your program again so that, instead of taking Z as input, it runs through all values of Z from 1 to 100 and prints out the most stable value of A for each one. At what value of Z does the maximum binding energy per nucleon occur? (The true answer, in real life, is Z=28, which is nickel.)