Q # 1 A particle with charge 5nC is placed in a uniform electric field at rest; the electric field is directed to the left. In addition to the electric force, a second force acts on the charge so that it moves to the right. When the charge has moved 16 cm to the right, its kinetic energy is 5 x 10-5 J and the second force has done 9 x 10- J of work on the charge. a ) How much work did the electric force do on the charge? b ) What is the potential difference from the charge's final position to its initial position? ( ) What is the strength of the uniform electric field? d ) If we repeated this experiment with a -5nC charge moving right in the same electric field, and if the work done by the second force were the same, would the final kinetic energy be higher or lower than 5 x 10-5 J