Question
Q) Circle the correct choice in the following: This takes care of scheduling and synchronization between multiple processors Control unit Hardwired Control Operating System All
Q) Circle the correct choice in the following:
This takes care of scheduling and synchronization between multiple processors
Control unit
Hardwired Control
Operating System
All of the above
Compared the CISC, RISC architecture has
Simpler opcode
Simple addressing modes
Fewer load/store
All of the above
The number of instruction types available in the CISC architecture makes the program, a) Smaller
Longer
Does not change
None of the above
Storage space that has the fastest access time
Cache
Main Memory
Hard drive
Registers
Split caches indicate separate
L1 and L2 cache
L2 and L3 cache
Data and Instruction cache
None of the above
In pipelining there is a requirement of this between stages
Memory
Registers
Buffer
None of the above
The main difference(s) between (BSA add) instruction that found in Basic computer and interrupt service routine is:
The location of storing the return address.
The time that must jump to the routine.
The return method to the main program.
a and b.
No one of the above.
If Register R which has (C7)h is shifted arithmetic right then its content will be:
(8E)h
(E3)h
(63)h
No one of the above.
If each memory access time = 2 msec. (and any other time is neglected) and the content of Ac= (7400)h then the time required to execute the following program that found in memory of basic computer is:
6 msec. SPA
10 msec. ADD @ 300
12 msec. INR
8 msec. HLT
No one of the above.
The list of memory instructions is different from the list of I/O in:
Memory-mapped programmed I/O
Isolated programmed I/O
a and b.
No one of the above
The INR control signal for PC register for the following system that consists of (AR, DR, PC, Ac) registers and each one consists of 4 bits and has three control signals (CLR, INR, Load):
T1 x: Ac PC, M[AR] DR
T3 y: Ac Ac + DR, PC PC+1, AR AR + 1
T0 z: DR M[AR], IF Ac=(FF)h then PC PC+1
T2 x: M[AR] PC , Ac 0
T3 y
(T3 y) (T0 z)
(T3 y) (T0 z)
(T3 y) ((T0 z) Ac =(FF)h)
(T3 y) ((T0 z) Ac =(FF)h)
No one of the above.
For the system described in point (11), the RD signal for M is:
T0 z
(T1 x) (T2 x)
(T1 x) (T2 x)
No one of the above.
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