Q1: For a basic computer that is currently running in its timing (TO) of execution for an instruction that resides in memory location 40F. what will be the contents of PC, AR, AC, IR, SC after the executions end of the next instruction. Where the content of AC is 1D2B and DR is 3CD7. The contents of memory locations are as following (Memory location: content):(40E: 7100): (40F: 7010): (410: 7200): (411: D732): (412:7004): (732:0891): (891:012A): (892:F200) Answer the next five sub-questions based on the above information: Q1-A: The content of PC is: 411 412 892 891 Q1-B: The content of AR is: 892 200 010 0732 Q1-C: The content of AC is: 0732 E2D4 102B None of the selections Q1-D: The content of IR is: 7200 D732 None of the selections 7010 Q1-E: The content of SC is: 3 5 0