Q1:

The average number of hours of TV viewingper household per week in Australia is49hours. Suppose the standarddeviation is21hours anda random sample of37Australian households is taken,

What is the probability that the sample average is less than57hours

Q2:

The average number of hours of TV viewingper household per week in Australia is 50hours. Suppose the standarddeviation is23hours anda random sample of34Australian households is taken,

What is the probability that the sample average is greater than57hours

Q3:

Use the following information to construct the confidence intervals specified toestimate 90% confidence interval for

x=95

=11.5,andn=53.

Lower Confidence Limit (L.C.L)=

Upper Confidence Limit (U.C.L)=

Q4:

A random sample ofn=15 items is taken, producing a sample mean ofx=13with asample variance ofs^2=4.7

Assume x is normally distributed and construct a 90%confidence interval for the population mean

Lower Confidence Limit (L.C.L)=

Upper Confidence Limit (U.C.L)=