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.. Q1.17 Sulphuric acid reacts with sodium hydroxide as follows H2SO4 + 2NaOH Na2SO4 + 2H20 When 11 of 0.1M sulphuric acid solution is allowed
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Q1.17 Sulphuric acid reacts with sodium hydroxide as follows H2SO4 + 2NaOH Na2SO4 + 2H20 When 11 of 0.1M sulphuric acid solution is allowed to react with 1L of 0.1M sodium hydroxide solution, the amount of sodium sulphate formed and its molarity in the solution obtained is (a) 0.1 mol L-1 (b) 7.10 g (c) 0.025 mol L-1 (d) 3.55 g 1 1Step by Step Solution
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