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Q3 (25%). Following ordinary differential equation (ODE) is given with the initial conditions: d'y day dy dt2 +36 +36y = 1 y(0) = y'() =

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Q3 (25%). Following ordinary differential equation (ODE) is given with the initial conditions: d'y day dy dt2 +36 +36y = 1 y(0) = y'() = y" (0) = 0 de +11 dt a) Apply partial fraction expansion and Heaviside expansion to find the solution, y(t). (20 pts) b) Find y(4). (5 pts)

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